First slide

Angular momentum

Question

A ring of diameter 0.4 m and mass 10 kg is rotating about its axis at the rate of 1200 rpm. The angular momentum of the ring is

Easy

A

$60.28 kg \cdot m^{2} s^{- 1}$
B

$55.26 kg \cdot m^{2} s^{- 1}$
C

$40.28 kg - m^{2} s^{- 1}$
D

$50.28 kg - m^{2} s^{- 1}$

Solution

Here, r = 0.2 m, M = 10 kg, v = 1200 rpm = 20 rps
$∴$ Angular momentum, $L = I ω = (M r^{2}) (2 π v)$
$= 10 \times (0.2)^{2} \times 2 \times \frac{22}{7} \times 20 = 50.28 kg - m^{2} s^{- 1}$

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