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A ring of diameter 0.4 m and mass 10 kg is rotating about its axis at the rate of 1200 rpm. The angular momentum of the ring is
detailed solution
Correct option is D
Here, r = 0.2 m, M = 10 kg, v = 1200 rpm = 20 rps∴ Angular momentum, L=Iω=Mr2(2πv)=10×(0.2)2×2×227×20=50.28 kg-m2 s-1Talk to our academic expert!
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A particle moving in a circular path has an angular momentum of L. If the frequency of rotation is halved, then its angular momentum becomes [Kerala CEE 2013]
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