A ring and a disc are initially at rest, side by side, at the top of an inclined plane which makes an angle 60° with the horizontal. They start to roll without slipping at the same instant of time along the shortest path. If the time difference between their reaching the ground is 2−3/10s , then the height of the top of the inclined plane, in meters, is ____________.Take g=10m/s2.
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answer is 0.75.
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Detailed Solution
ac=gsinθ1+ICMR2 aring =gsinθ2,adisc =2gsinθ3 For ring hsinθ=12gsinθ2t12⇒t1=4hgsin2θ=16h3g For disc, hsinθ=122gsinθ3t22⇒t2=3hgsin2θ=4hg Given :t2−t1=16h3g−4hg=2−310⇒h43−2=2−3⇒h=(2−3)3(4−23)=32⇒h=0.75m
A ring and a disc are initially at rest, side by side, at the top of an inclined plane which makes an angle 60° with the horizontal. They start to roll without slipping at the same instant of time along the shortest path. If the time difference between their reaching the ground is 2−3/10s , then the height of the top of the inclined plane, in meters, is ____________.Take g=10m/s2.