First slide
Moment of intertia
Question

A ring has a mass of 0.5 kg and radius 1 m. The moment of inertia of the ring about its diameter is

Easy
Solution


Ix = Iy
Again, Ix + Iy = Iz
\large \Rightarrow I_x=\frac 12I_z=\frac 12mR^2
\large =\frac 12\times0.5\times(1)^2\;kg-m^2
\large =0.25kg\;-m^2

 

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