A ring is kept on a rough inclined surface. But the coefficient of friction is less than the minimum value required for pure rolling. At any instant of time, let KT and KR be the translational and rotational kinetic energies of the ring respectively, then
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a
KR = KT
b
KR > KT
c
KT > KR
d
KR = 0
answer is C.
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Detailed Solution
Friction in this case is backward. If it is insufficient, it is the case of forward slipping or KT > KR