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A ring of mass 3 kg is rolling without slipping with linear velocity 1 ms-1 on a smooth horizontal surface. A rod of same mass is fitted along its one diameter. Find total kinetic energy of the system (in J).

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answer is 5.

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Detailed Solution

K=KR+KT=12mR2+m(2R)212VR2+12(2m)V2=53mv2=53(3)(1)2=5 J

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A ring of mass 3 kg is rolling without slipping with linear velocity 1 ms-1 on a smooth horizontal surface. A rod of same mass is fitted along its one diameter. Find total kinetic energy of the system (in J).