First slide
Moment of intertia
Question

A ring of mass M and radius R lies in x-y plane with its centre at origin as shown. The mass distribution of ring is non uniform such that, at any point P on the ring, the mass per unit length is given by λ = λ0cos2θ (where λ0 is a positive constant). Then the moment of inertia of the ring about z-axis is:

Moderate
Solution

Divide the ring into infinitely small lengths of mass dmi. Even though mass distribution is non-uniform, each mass dmi is at same distance R from origin.
  MI of ring about z-axis is
dm1R2+dm2R2+....+dmnR2 = MR2

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