A ring of radius R is first rotated with an angular velocity ω0 and then carefully placed on a rough horizontal surface. The coefficient of friction between the surface and the ring is μ. Time after which its angular speed is reduced to half is
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a
ω0μR2g
b
ω0g2μR
c
2ω0Rμg
d
ω0R2μg
answer is D.
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Detailed Solution
Taking τ about CMμmgR=MR2αμg=Rαα=μgRω=ω0−μgRt=ω02⇒ω02=μgRt⇒t=ω0R2μg