First slide
Dynamics of rotational motion about fixed axis
Question

A ring of radius R is first rotated with an angular velocity ω0 and then carefully placed on a rough horizontal surface. The coefficient of friction between the surface and the ring is µ. Time after which its angular speed is reduced to half is

Moderate
Solution


IC = MR2, fk = µMg
 

\large \therefore \alpha =\frac {\tau}{I_C}=\frac {f_k.R}{MR^2}


 

\large =-\frac {\mu MgR}{MR^2}=-\frac {\mu g}{R}

 

\large \omega =\omega _0+\alpha t\Rightarrow \frac {\omega _0}{2}=\omega _0-\frac {\mu g}{R}t \Rightarrow t=\frac {\omega _0R}{2\mu g}

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