A ring of radius R has charge -Q distributed uniformly over it. A charge q is placed at the centre of the ring such that the electric field becomes zero at a point on the axis of the ring distant R from the centre of the ring. The value of charge q is

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Q23

Q42

Q32

Q43

answer is B.

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Detailed Solution

Electric field at point P due to charge of ring isE=kQxR2+x23/2 At x=R:E=kQ22R2 directedtowardsthecentre. Electric field at P due to centre charge:kgR2For net field to be zero at P:kqR2=kQ22R2⇒q=Q22=Q42.

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