A ring of radius R has charge -Q distributed uniformly over it. A charge q is placed at the centre of the ring such that the electric field becomes zero at a point on the axis of the ring distant R from the centre of the ring. The value of charge q is
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a
Q23
b
Q42
c
Q32
d
Q43
answer is B.
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Detailed Solution
Electric field at point P due to charge of ring isE=kQxR2+x23/2 At x=R:E=kQ22R2 directedtowardsthecentre. Electric field at P due to centre charge:kgR2For net field to be zero at P:kqR2=kQ22R2⇒q=Q22=Q42.