First slide
Electric field
Question

A ring of radius R has charge -Q distributed uniformly over it. A charge q is placed at the centre of the ring such that the electric field becomes zero at a point on the axis of the ring distant R from the centre of the ring. The value of charge q is 

Moderate
Solution

Electric field at point P due to charge of ring is

E=kQxR2+x23/2

 At x=R:E=kQ22R2 directedtowardsthecentre

Electric field at P due to centre charge:kgR2

For net field to be zero at P:

kqR2=kQ22R2q=Q22=Q42.

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