Download the app

Questions  

A ring of radius R has uniformly distributed charge. It spins about its axis with an angular velocity ω . P is a point on its axis at a distance x, from its centre. The velocity of light in vaccum is c. Then the ratio of magnetic field to the electric field at P is equal to

a
x2cR2ω2
b
xc2ωR2
c
ω2Rx2c
d
ωR2xc2

detailed solution

Correct option is D

E = Qx4πεoR2+x232;    B = μoQωR24πR2+x232 ∴  BE = μoεoωR2x = ωR2xc2 ∴c = 1μoεo

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

A charged particle of mass 2 x 10-12 kg carrying a charge of 4 x 10-9 coul is projected in a uniform magnetic field of 2 x 10-4 tesla with a velocity of 10 m/s making an angle of 60° with the magnetic field. If acceleration due to gravity in that field is zero, then length of path praversed by the particle in 1 minute is 


phone icon
whats app icon