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Q.

A ring of radius R has uniformly distributed charge. It spins about its axis with an angular velocity ω . P is a point on its axis at a distance x, from its centre. The velocity of light in vaccum is c. Then the ratio of magnetic field to the electric field at P is equal to

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a

x2cR2ω2

b

xc2ωR2

c

ω2Rx2c

d

ωR2xc2

answer is D.

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Detailed Solution

E = Qx4πεoR2+x232;    B = μoQωR24πR2+x232 ∴  BE = μoεoωR2x = ωR2xc2 ∴c = 1μoεo
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