First slide
Nature of electromagnetic wave
Question

A ring of radius R has uniformly distributed charge. It spins about its axis with an angular velocity ω . P is a point on its axis at a distance x, from its centre. The velocity of light in vaccum is c. Then the ratio of magnetic field to the electric field at P is equal to

Easy
Solution

E=Qx4πεoR2+x232;    B=μoQωR24πR2+x232   BE=μoεoωR2x=ωR2xc2c=1μoεo

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App