A ring of radius R has uniformly distributed charge. It spins about its axis with an angular velocity ω . P is a point on its axis at a distance x, from its centre. The velocity of light in vaccum is c. Then the ratio of magnetic field to the electric field at P is equal to
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a
x2cR2ω2
b
xc2ωR2
c
ω2Rx2c
d
ωR2xc2
answer is D.
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Detailed Solution
E = Qx4πεoR2+x232; B = μoQωR24πR2+x232 ∴ BE = μoεoωR2x = ωR2xc2 ∴c = 1μoεo