Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

A ring of radius R having a linear charge density λ moves towards a solid imaginary sphere of radius R2,so that the centre of ring passes through the centre of sphere. The axis of the ring is perpendicular to the line joining the centres of the ring and the sphere. If the maximum flux through the sphere in this process is found to be λπRnϵ0, , find the value of n.

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

answer is 3.0.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Electric flux will be maximum when maximum length of ring isinside the sphere. This will occur when the length of the chord AB is maximum. Now maximum length of chord AB can be the diameter of the ring. In this case the arc of ring inside the sphere subtends an angle of π/3 at the centre of ring. Thus charge on this arc in this situation is given asq=Rπ3⋅λ⇒ϕ=Rπ3λϵ0=Rπλ3ϵ0
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon