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Gravitational force and laws

Question

A ring of radius R = 4 m made of a highly dense material has a mass m1=5.4×109kg distributed uniformly over its circumference. A highly dense particle of mass m2=6×108kg is placed on the axis of the ring at a distance 3 m from the center of the ring. Find the speed of the particle (in cm/s), when the particle is at the center of the ring. Except mutual gravitational interaction of the two, neglect all other forces.

Moderate
Solution

When the particle is at the center, let their respective speeds
are v1 and v2.
From conservation of linear momentum,

 0=5.4×109v16×108v2 v2=9v1

From conservation of energy, (U+K)i=(U+K)f

Gm1m242+32+0=Gm1m24+12m1v12+12m2v22Gm1m21415=12m1v12+12m281v12G9m2220=1290m2v12m1=9 m2

 Now m1=9m2 (given) 

v1=Gm2100=6.67×1011×6×108100=0.02ms1 v2=9v1=0.18ms1=18cms1



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