Questions
A ring is rolling on a surface without slipping. What is the ratio of its translational to rotational kinetic energies ?
a
5:7
b
2:5
c
2:7
d
1:1
detailed solution
Correct option is D
Translational K.E.=12mv2Rotational K.E. =12Iω2=12mR2ω2∵ For a ring I=mR2=12m(ωR)2=12mv2So, translational K.E. = rotational K.E.∴ translational K.E. : rotational K,E. = 1 :1Talk to our academic expert!
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