The ring shown in figure is given a constant horizontal acceleration a0=g/3. The maximum deflection of the string from the vertical θ0. Then

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

θ0=30∘

θ0=60∘

At maximum deflection, tension in string is equal to mg.

At maximum deflection, tension in string is equal to 2mg3.

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Tcos⁡θ0=mg .......(i)Tsin⁡θ0=ma0 .......(ii)Dividing Eq. (ii) by (i), we get tan⁡θ0=ag⇒θ0=30∘T=mgcos⁡30∘=2mg3

Watch 3-min video & get full concept clarity