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A ring starts from rest and acquires an angular speed of 10 rad in 2 s. The mass of the ring is 500 gm and its radius is 20 cm. The torque on the ring is
detailed solution
Correct option is C
α = ωt = 102 = 5rad/s2 τ = Iα = MR2α = 0.500×(0.20)2×5 = 0.10 NmTalk to our academic expert!
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