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Q.

A ring starts from rest and acquires an angular speed of 10 rad/s in 2 s. The mass of the ring is 500 g and its radius is 20 cm. The torque on the ring is

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a

0 .02 Nm

b

0 .20 Nm

c

0. 10 Nm

d

0 .01 Nm

answer is C.

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Detailed Solution

α=(10/2)rad/s2=5rad/s2I=MR2=12(0⋅2)2=0⋅02kg−m2τ=Iα=5×0⋅02=0⋅10Nm
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