First slide

Viscous flow/Laminar flow

Question

A river 10 m deep is flowing at 5 ms^-1. The shearing stress between horizontal layers of the river it ( $η = 10^{- 3}$ SI units)

Easy

A

$10^{- 3} N / m^{2}$
B

$0.8 \times 10^{- 3} N / m^{2}$
C

$0.5 \times 10^{- 3} N / m^{2}$
D

$1 N / m^{2}$

Solution

$Shearing stress = \frac{∣ viscous force ∣}{area}$
$\begin{matrix} = \frac{η A \frac{d v}{d x}}{A} = η \frac{d v}{d x} \\ = 10^{- 3} \times \frac{5}{10} N / m^{2} = 0.5 \times 10^{- 3} N / m^{2} \end{matrix}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App