A river is of width 100 m which flows at a speed of 10 ms−1 . If a man swims with a speed of2 ms−1 at an angle of 1350 with the stream, his drift on reaching other bank is

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50 m

900 m

200 m

300 m

answer is B.

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Detailed Solution

x=d[Vw−VbsinθVbcosθ] =100[10−2sin452cos45] =100[10−11]=900m

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