First slide

Alternating Current and voltage

Question

The r.m.s. value of an ac of 50 Hz is 10 amp. The time taken by the alternating current in reaching from zero to maximum value and the peak value of current will be

Moderate

A

2 $\times$ 10^–2 sec and 14.14 amp
B

1 $\times$ 10^–2 sec and 7.07 amp
C

5 $\times$ 10^–3 sec and 7.07 amp
D

5 $\times$ 10^–3 sec and 14.14 amp

Solution

Time taken by the current to reach the maximum value $t = \frac{T}{4} = \frac{1}{4 ν} = \frac{1}{4 \times 50} = 5 \times 10^{- 3} \sec$
and $i_{o} = i_{rms} \sqrt{2} = 10 \sqrt{2} = 14 .14$ amp

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App