Electromagnetic waves and its nature

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Question

The rms values of the electric field of the light coming from sun is 1000 N/C. The average energy density of the EM wave is _____ $\times$ 10^–6 J/m³

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Solution

In electromagnetic waves, electric energy density is equal to magnetic energy density.
Total energy density = 2 $\times$ electric energy
$\begin{array}{l} = 2 (\frac{1}{4} ε_{0} {E_{0}}^{2}) \\ = \frac{1}{2} \times 8.854 \times 10^{- 12} \times (1000 \sqrt{2})^{2} \\ = 8.854 \times 10^{- 6} J / m^{3} \end{array}$

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