Questions
A rock of mass m is dropped to the ground from a height h. A second rock with mass 2m is dropped from the same height. When second rock strikes, the ground, what is its K.E.?
detailed solution
Correct option is A
final velocity of the body dropped from height h is V = 2gh K.E.= 12 mv2 for the first body KE= 12 mv2 for the second body KE= 12 (2m)v2=twice KE of first bodyTalk to our academic expert!
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