Q.

A rock of mass m is dropped to the ground from a height h.  A second rock with mass 2m is dropped from the same height.  When second rock strikes, the ground, what is its K.E.?

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a

Twice that of the first rock

b

four times that of the first rock

c

the same as that of the first rock

d

half that of the first rock

answer is A.

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Detailed Solution

final velocity of the body dropped  from height h is    V  =   2gh K.E.=   12 mv2 for the first body KE=   12 mv2 for the second body KE=   12 (2m)v2=twice KE of first body
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