A rocket is fired vertically up from the ground with a resultant acceleration of 10 m/s2, The fuel is finished in 1 min and it continues to move up g=10 m/s2
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a
the maximum height reached by rocket from ground is 18 km
b
the maximum height reached by rocket from ground is 36 km
c
the time from initial when rocket is again at ground is (180+302)s
d
the time from initial when rocket is again at ground is (120+602)s
answer is B.
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Detailed Solution
At 60 s,h1=12×10×(60)2=18000 m v1=10×60=600 m/sAfter thath2=v122g=18000 m Hmax=h1+h2 =36000 m=36 kmFurther, -18000=600t-5t2or t2-120t-3600=0or t=120+14400+144002=120+12022=60+602∴ Total time =60+(60+602)=(120+602)s