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A rocket is fired vertically up from the ground with a resultant acceleration of $10 m / s^{2}$ , The fuel is finished in $1$ min and it continues to move up $(g = 10 m / s^{2})$

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the maximum height reached by rocket from ground is 18 km

the maximum height reached by rocket from ground is 36 km

the time from initial when rocket is again at ground is (180+302)s

the time from initial when rocket is again at ground is (120+602)s

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detailed solution

Correct option is B

At 60 s,h1=12×10×(60)2=18000 m v1=10×60=600 m/sAfter thath2=v122g=18000 m Hmax=h1+h2 =36000 m=36 kmFurther, -18000=600t-5t2or t2-120t-3600=0or t=120+14400+144002=120+12022=60+602∴ Total time =60+(60+602)=(120+602)s

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A rocket is fired vertically up from the ground with a resultant acceleration of 10 m/s2, The fuel is finished in 1 min and it continues to move up g=10 m/s2

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A rocket is fired vertically up from the ground with a resultant acceleration of $10 m / s^{2}$ , The fuel is finished in $1$ min and it continues to move up $(g = 10 m / s^{2})$