Download the app

Questions  

A rocket of mass 1000 kg is to be projected vertically upwards. The gases are exhausted vertically downwards with velocity 100 ms-1 with respect to the rocket. What is the minimum rate
of burning of fuel, so as to just lift the rocket upwards against the gravitational attraction?
(Take, g = 10 ms-2) [AMU 2011] 

a
50 kg s-1
b
200 kg s-1
c
100 kg s-1
d
400 kg s-1

detailed solution

Correct option is B

The velocity of exhaust gases with respect to the rocket=100 ms-1The minimum force on the rocket to lift it,Fmin=mg=1000×10=10000 NHence. minimum rate of burning of fuel is given bydmdt=Fwin v=10000100=100kgs-1

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

In the figure given the position-time graph of a particle of mass 0.1 kg is shown. The impulse at t = 2 s is :
 


phone icon
whats app icon