Question

A rocket of mass 40 kg has 160 kg fuel. The exhaust velocity of the fuel is 2 kms^-1 .The rate of consumption of fuel is 4 kgs^-1 .Calculate the ultimate vertical speed gained by the rocket.

Moderate

Solution

$V = u_{o} + {ulog}_{e} (\frac{m_{0}}{m}) = 4 \log_{e} (\frac{200}{40}) = 2 \log_{e} (5) = 2 \log_{e} (\frac{10}{2}) = 2.82$

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