A rocket set for vertical firing with a resultant acceleration of $$50m/s2$$ .If the fuel is finished $$2$$ minutes then the maximum height reached by the rocket $$g=10m/s2$$

Question

A rocket set for vertical firing with a resultant acceleration of $$50m/s2$$ .If the fuel is finished $$2$$  minutes then the maximum height reached by the rocket $$g=10m/s2$$

Infinity Learn · Accepted Answer

The height attained by rocket in $$2$$ minutes is  by question,intial $$velocity=U=0$$, $$acceleration=$$ $$a=50$$ $$m/s2$$, $$time=$$  $$t=2$$×$$60=120sec$$ ;$$displacement=$$  $$S=h1$$  we know, $$S=Ut+12at2$$ ⇒$$h1=1250$$×$$120$$×$$120$$ ⇒$$h1=360km---(1)Velocity$$ gained by the rocket , in $$120sec$$ is   $$V=U+at$$, substitute given values $$V=0+50$$×$$120=6000m/s$$  The height attained after $$2$$ minutes $$=h2=V22g$$         (obtained$$ from equation of $$motion) ⇒$$h2=600022$$×$$10=1800000m$$ ⇒$$h2=1800kmTotal$$ height attained by rocket $$H=h1+h2=360+1800=2160km$$

A rocket set for vertical firing with a resultant acceleration of $50 m / s^{2}$ .If the fuel is finished 2 minutes then the maximum height reached by the rocket $(g = 10 m / s^{2})$

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A rocket set for vertical firing with a resultant acceleration of 50m/s2 .If the fuel is finished 2 minutes then the maximum height reached by the rocket g=10m/s2

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A rocket set for vertical firing with a resultant acceleration of $50 m / s^{2}$ .If the fuel is finished 2 minutes then the maximum height reached by the rocket $(g = 10 m / s^{2})$