A rocket set for vertical firing with a resultant acceleration of 5m/s2 if the fuel is finished 2  minutes then the maximum height reached by the rocket g=10m/s−2

U=0,  a=5 m/s2,   t=2×60=120sec   S=h1From  S=Ut+12at2⇒h1=125×120×120⇒h1=36kmVelocity gained by the rocket from  V=U+at,V=0+5×120=600m/s The height attained after 2 sec is  h2=V22g⇒h2=60022×10=18000m⇒h2=18kmTotal height attained by pocket H=h1+h2=36+18=54km