A rocket set for vertical firing with a resultant acceleration of $$5m/s2$$. If the fuel is finished in $$2$$ minutes, then the maximum height reached by the rocket is $$g=10m/s$$−$$2$$

Question

A rocket set for vertical firing with a resultant acceleration of $$5m/s2$$. If the fuel is finished in $$2$$  minutes, then the maximum height reached by the rocket  is $$g=10m/s$$−$$2$$

Infinity Learn · Accepted Answer

The height attained by rocket in $$2$$ minutes is  by the question, initial $$velocity=U=0$$;acceleration $$=$$ $$a=5$$ $$m/s2$$;time $$elapsed=t=2$$×$$60=120sec$$;$$displacement=S=h1$$  $$S=Ut+12at2$$ ⇒$$h1=125$$×$$120$$×$$120$$ ⇒$$h1=36km---(1)Velocity$$ gained by the rocket from  $$V=U+at$$,$$V=0+5$$×$$120=600m/s$$ The height attained after $$2$$ minutes is  $$h2=V22g$$⇒$$h2=60022$$×$$10=18000m$$⇒$$h2=18kmTotal$$ height attained by rocket $$H=h1+h2=36+18=54km$$

A rocket set for vertical firing with a resultant acceleration of $5 m / s^{2} .$ If the fuel is finished in 2 minutes, then the maximum height reached by the rocket is $(g = 10 m / s^{- 2})$

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A rocket set for vertical firing with a resultant acceleration of 5m/s2. If the fuel is finished in 2 minutes, then the maximum height reached by the rocket is g=10m/s−2

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A rocket set for vertical firing with a resultant acceleration of $5 m / s^{2} .$ If the fuel is finished in 2 minutes, then the maximum height reached by the rocket is $(g = 10 m / s^{- 2})$