A rod AB of uniform cross-sectional area is subjected to an axial tensile force F. If the maximum normal force induced in the rod is 8 KN/cm2, the maximum shear stress induced in the rod will be

If S be the cross sectional area of the rod, Then  σmax=FSNow area of cross section MN=S/sinθComponent of applied force along MN=Fcosθ∴ Shear stress on the section MN=τ=Fcosθs/sinθ=F2Ssin2θWhen θ=45o, τ=τmax=F2S=σ2=82KNcm2=4 KNcm2