First slide

Magnetisation and magnetic intensity

Question

A rod of cross sectional area 10 cm² is placed with its length parallel to a magnetic field of intensity 1000 A/m the flux through the rod is 10⁴ weber. Then the permeability of material of rod is

Moderate

A

10⁴ wb/Am
B

10³ wb/Am
C

10² wb Am
D

10 wb Am

Solution

$\begin{array}{rcl} ϕ & = & BA = μHA; \\ 10^{4} & = & μ x 10^{3} x 10^{- 3} \\ μ & = & 10^{4} \frac{wb}{Am} \end{array}$

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