A rod of cross sectional area 10 cm2 is placed with its length parallel to a magnetic field of intensity 1000 A/m the flux through the rod is 104 weber. Then the permeability of material of rod is

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104 wb/Am

103 wb/Am

102 wb Am

10 wb Am

answer is A.

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Detailed Solution

ϕ=BA=μHA ; 104=μ x 103 x 10-3μ=104wbAm

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