A rod of length 50cm is pivoted at one end. It is raised such that it makes an angle 300 from the horizontal as shown and released from rest. Its angular speed when it passes through the horizontal (in rad/s ) will be ( g=10m/s2)

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answer is 0005.48.

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Detailed Solution

According to Law of Conservation of Energy⇒mgl2sin⁡30=12Iω2⇒mgl212=12ml23ω2⇒ω=3g2l=30=5.48 rad/s

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