Questions
A rod of length L and mass M is acted on by two unequal forces F1 and F2 (> F1) as shown in the following figure
The tension in the rod at a distance y from the end A is given by
detailed solution
Correct option is A
a=F2−F1Mm=yMLT−F1=ma=F2−F1MyMLT=F1+F2−F1yL∴T=F11−yL+F2yLTalk to our academic expert!
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