Questions
A rod of length L and mass M is acted on by two unequal forces F1 and F2 (> F1) as shown in the following figure
The tension in the rod at a distance y from the end A is given by
detailed solution
Correct option is A
a=F2−F1M m=yM1 T−F1=ma=F2−F1MyML T=F1+F2−F1yL ∴T=F11−yL+F2yLTalk to our academic expert!
Similar Questions
In fig., the blocks are of equal mass. The pulley
is fixed. In the position shown, A moves with a speed u and the speed of B is v. Then
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
