Questions
A rod of length L and mass M is acted on by two unequal force F1 and F2 (< F1) as shown in fig.
The tension in the rod at a distance x from end B will be
detailed solution
Correct option is B
Net force on the rod = F1 - F2∴ Acceleration of the rod=F1−F2/MNow consider t}re motion of part BC. Mass of this part = (M / L) x. ThenF1−T=MLxawhere I is the tension at point C. SoF1−T=MLxF1−F2M=F1−F2xLor T=F1−F1−F2xLor T=F11−xL+F2xL.Talk to our academic expert!
Similar Questions
Two forces are acting on a rope lying on a smooth table as shown in figure.
Which of the following statement (s) is/are correct?
I. In moving from A to B, tension on string decreases from 2F to F.
II. Situation will becomes indeterminant, if we take it a massless string.
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