A rod of length land negligible mass is suspended at its two ends by two wires of steel (wire A) and aluminium (wire B) of equal lengths Fig. The cross-sectional areas of wires A and Bare 1.0 mm2 and 2.0 mm2, respectively.(YAl= 70 x 109 Nm-2 and Ysteel=200 X 109 Nm-2) (i) Mass m should· be suspended close to wire A to have equal stresses in both the wires.(ii) Mass m should be suspended close to wire B to have equal stresses in both the wires.(iii) Mass m should be suspended at the middle of the wires to have equal stresses in both the wires.(iv) Mass m should be suspended close to wire A to have equal strains in both the wires.
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
(i, ii)
b
(i, iii)
c
(ii, iii)
d
(ii, iv)
answer is D.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
IF the stress in both the wires are equal then for rotational equilibrium mass m should be close to wire B.IF the strains in both the wires are equal then for translational equilibrium mass m should be nearer to wire A.