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Q.

A rod of length land negligible mass is suspended at its two ends by two wires of steel (wire A) and aluminium (wire B) of equal lengths Fig. The cross-sectional areas of wires A and Bare 1.0 mm2 and 2.0 mm2, respectively.(YAl= 70 x 109 Nm-2 and Ysteel=200 X 109 Nm-2) (i) Mass m should· be suspended close to wire A to have equal stresses in both the wires.(ii) Mass m should be suspended close to wire B to have equal stresses in both the wires.(iii) Mass m should be suspended at the middle of the wires to have equal stresses in both the wires.(iv) Mass m should be suspended close to wire A to have equal strains in both the wires.

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a

(i, ii)

b

(i, iii)

c

(ii, iii)

d

(ii, iv)

answer is D.

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Detailed Solution

IF the stress in both the wires are equal then for rotational equilibrium mass m should be close to wire B.IF the strains in both the wires are equal then for translational equilibrium mass m should be nearer to wire A.
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A rod of length land negligible mass is suspended at its two ends by two wires of steel (wire A) and aluminium (wire B) of equal lengths Fig. The cross-sectional areas of wires A and Bare 1.0 mm2 and 2.0 mm2, respectively.(YAl= 70 x 109 Nm-2 and Ysteel=200 X 109 Nm-2) (i) Mass m should· be suspended close to wire A to have equal stresses in both the wires.(ii) Mass m should be suspended close to wire B to have equal stresses in both the wires.(iii) Mass m should be suspended at the middle of the wires to have equal stresses in both the wires.(iv) Mass m should be suspended close to wire A to have equal strains in both the wires.