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Q.

A rod of length 6 m has specific gravity ρ(=25/36). One end of the rod is tied to a 5 m long rope, which in turn is tied to the floor of a pool 10 m deep, as shown. Find the length (in m) of the part of rod which is out of water.

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answer is 1.

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Detailed Solution

(6−x)2Aρωg2=18AρrgSolving we get x = 1 m.
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