First slide

Conduction

Question

A rod of length 1 m having cross-sectional area 0.75 m² conducts heat at 6000 Js^–1. Then the temperature difference acorss the rod is, if K = 200 Wm^–1 K^–1

Easy

A

20⁰ C
B

40⁰ C
C

80⁰C
D

100⁰C

Solution

$\large \frac {Q}{t}=\frac {kA(\theta_1-\theta_2)}{l}$
$\large \Rightarrow 6000=\frac {200(0.75)(\theta_1-\theta_2)}{(1)}$
$\large \Rightarrow \theta_1-\theta_2=40^0C$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App