Questions
A rod of mass 5 kg is connected to the string at point B. The span of rod is along horizontal. The other end
of the rod is hinged at point A If the string is massless, then the reaction of hinge at the instant when string
is cut, is (Take, 9 = 10 ms-2) [UP CPMT 2015]
detailed solution
Correct option is B
When string is cut, the weight of the rod constitutes a torque about the hinge point A.So, τA=mgl2 …(i)Also, from Newton's law, τA=Iα …(ii)where, α = angular acceleration of the rodand I = moment of inertia of rod.From Eqs. (i) and (ii), we getIα=mgl2⇒α=mgl2/IAs, I=ml23So, α=mg(l/2)ml23=3g2lNow, acceleration of centre of mass of rod, aCM=α⋅rHere, r = distance between hinge point A and centre of the rod.⇒ aCM=32gll2=3g4⇒ mg−RA=maCMwhere, RA = reaction at A.⇒ mg−RA=m×3g4⇒RA=mg4=5×104=12.5NTalk to our academic expert!
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