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A rod of mass M kg and length L m is bent in the form of an equilateral triangle as shown in Fig. The moment of inertia of the triangle about a vertical axis perpendicular to the plane of the triangle and passing through the centre O (in units of kg m2) is

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a
ML212
b
ML254
c
ML2162
d
ML2108

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detailed solution

Correct option is B

Mass of each side = M3x = 13[L3cos 30°] = L323moment of inertia of one side about O:I = [112M3(L3)2+M3x2] = ML2162moment of inertia of whole triangle about O : 3I = ML254


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The moment of inertia of a thin uniform rod of mass M and length L about an axis passing through its mid-point and perpendicular to its length is I0 , Its moment of inertia about an axis passing through one of its ends and perpendicular to its length is


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