First slide

Potential energy

Question

A rod of mass m and length I is lying on a horizontal table. Work done in making it stand on one end will
be

Moderate

A

$m g l$
B

$\frac{m g l}{2}$
C

$\frac{m g l}{4}$
D

2 $m g l$

Solution

Centre of mass of the rod moves a height, $h = \frac{l}{2} .$
Work done, W = mgh = mgl / 2

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