First slide

Torque

Question

A rod PQ of mass M and length L is hinged at end P. The rod is kept horizontal by a massless string tied to point Q as shown in figure. When string is cut, the initial angular acceleration of the rod is :

Moderate

A

$\frac{2 g}{3 L}$
B

$\frac{3 g}{2 L}$
C

g/L
D

2g/L

Solution

$\begin{array}{l} τ = Iα \\ \Rightarrow mg (\frac{L}{2}) = (\frac{{ml}^{2}}{3}) α \\ \Rightarrow α = \frac{3 g}{2 L} \end{array}$

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