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Questions  

A rod PQ of mass M and length L is hinged at end P. The rod is kept horizontal by a massless string tied to point Q as shown in figure. When string is cut, the initial angular acceleration of the rod is

a
2gL
b
2g2L
c
3g2L
d
gL

detailed solution

Correct option is C

When the string is cut, the rod will rotate about P. Let α be initial angular acceleration of the rod. ThenTorque, τ=Iα=ML23α        −−−(i) ( ∵ Moment of inertia of the rod about one end =ML23 ) Also, τ=MgL2          −−−(ii) Equating (i) and (ii), we get MgL2=ML23α   or  α=3g2L

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