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Questions  

A rod PQ of mass m and resistance r is moving on two fixed, resistanceless, smooth conduction rails (closed on both sides by resistance R1  and R2 ). Find the current in the rod at the instant its velocity is v

 

a
i=BlVR1−R2
b
i=BlVr+R1+R2
c
i=BlVR1+R2
d
i=BlVr+R1R2R1+R2

detailed solution

Correct option is D

i=BlVr+R1R2R1+R2 This current equivalent to the following diagram

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Similar Questions

The diagram shows a circuit having a coil of resistance R=2.5Ω and inductance L connected to a conducting rod PQ which can slide on a perfectly conducting circular ring of radius 10 cm with its centre at 'P'. Assume that friction and gravity are absent and a constant uniform magnetic field of 5 T exists as shown in figure.

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