Q.
A rod PQ of mass m and resistance r is moving on two fixed, resistanceless, smooth conduction rails (closed on both sides by resistance R1 and R2 ). Find the current in the rod at the instant its velocity is v
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a
i=BlVR1−R2
b
i=BlVr+R1+R2
c
i=BlVR1+R2
d
i=BlVr+R1R2R1+R2
answer is D.
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Detailed Solution
i=BlVr+R1R2R1+R2 This current equivalent to the following diagram
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