A rod of weight W is supported by two parallel knife edges A and B and is in equilibrium in a horizontal position. The knives are at a distance d from each other. The centre of mass of the rod is at distance x from A. The normal reaction on A is

Question

Infinity Learn · Accepted Answer

Given situation is shown in figure. $$N1=$$ Normal reaction on $$AN2=$$ Normal reaction on $$BW=$$ Weight of the rod  In vertical equilibrium,  $$N1+N2=W$$                       . . . .(i)Torque$$ balance about centre of mass of the rod, $$N1x=N2(d-x)Putting$$ value of  $$N2$$ from equation $$(i)N1x=W-N1(d-x)⇒$$N1x=Wd-Wx-N1d+N1x$$⇒$$N1d=W(d-x)$$∴  $$N1=W(d-x)d$$

A rod of weight W is supported by two parallel knife edges A and B and is in equilibrium in a horizontal position. The knives are at a distance d from each other. The centre of mass of the rod is at distance x from A. The normal reaction on A is

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