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Q.

Rods AB,BC,CD, & DA are joined to form a square loop having current ‘i’. Mass and length of each rod is m & / respectively. This loop is situated in uniform magnetic field B→ as shown, and can rotate freely about axis p1p2 Match the following, if initially plane of the loop is parallel to magnetic field__ Angular acceleration of the loop at t = 0

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a

A-R;B-S;C-P;D-Q

b

A-P;B-Q;C-R;D-S

c

A-Q;B-R;C-S;D-Q

d

A-P;B-Q;C-P;D-Q

answer is A.

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Detailed Solution

A)M→=il2k→ ⇒B→=Bi→ τ→=M→×B→ ⇒τ→=il2k→×Bi→=Bil2j→⇒IP1P2=I02=4ml232=2ml23 ⇒τ=Iαα=τI=Bil22ml23=3Bi2mB) W=MB(cos(90-30)-cos90) ⇒12Iω2=il2B12-0 ⇒122ml23ω2=il2B12-0 ⇒ω=3Bi2mC)τ=MBsin(90-60)=il2B2D)τ=MBsin(0)Iα=MB(0) α=0
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Rods AB,BC,CD, & DA are joined to form a square loop having current ‘i’. Mass and length of each rod is m & / respectively. This loop is situated in uniform magnetic field B→ as shown, and can rotate freely about axis p1p2 Match the following, if initially plane of the loop is parallel to magnetic field__ Angular acceleration of the loop at t = 0