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In a room, where the temperature is 300C, a body cools from 610C to 590C in 4 min. The time taken by the body to cool from 510C to 490C will be [MP PMT 2013)

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a

4 min

b

5 min

c

6 min

d

8 min

answer is C.

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Detailed Solution

According to Newton's law of cooling,61−594=K61+592−30⇒ 24=K×30 Similarly, 51−49t=K51+492−30⇒ 2t=K×20Solving Eqs. (i) and (ii), we gett = 6 min

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In a room, where the temperature is 300C, a body cools from 610C to 590C in 4 min. The time taken by the body to cool from 510C to 490C will be [MP PMT 2013)