Questions
A rope of length 30 cm is on a horizontal rough table with maximum length hanging from edge ‘A’ of the table. The coefficient of friction between rope and table is 0.5. The distance of centre of mass of the rope from ‘A’ is
detailed solution
Correct option is B
μl−lnmg=mglnμ1−1n=1n0.5n−1n=1nn−1=2; n=3The total mass is m .The length of the rope hanging is I3 and the length of the rope on the table is 2I3 whose mass is equal to2m3→rcm2m3−10i^+m3−5j^m=−20i^−5j^3rcm=4009+259=4259=5173Similar Questions
Find the position of centre of mass of a uniform disc of radius R from which a hole of radius r is cut out. The centre of the hole is at a distance from the centre of the disc.
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