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Q.

A rope of rubber of density 1.5×103Kg/m3  and Young's modulus 5×106N/m2 , 8m in length is hung from the ceiling of a room. Then the increase in length due to its own weight is

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a

96×10−2m

b

12×10−4m

c

96×10−3m

d

12×10−3m

answer is C.

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Detailed Solution

e=ℓ2dg2y =82×1.5×103×102×5×106  =96×10-3 m
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A rope of rubber of density 1.5×103Kg/m3  and Young's modulus 5×106N/m2 , 8m in length is hung from the ceiling of a room. Then the increase in length due to its own weight is