A rope is stretched between two boats at rest. A sailor in the first boat pulls the rope with a constant force of 100 N. First boat with the sailor has a mass of 250 kg where as
the mass of second boat is double of this mass. If the initial distance between the boats was 120 m, the time taken for two boats to meet each other is (neglect water resistance between boats and water)

Question

Infinity Learn · Accepted Answer

The force of $$100$$ N acts on both the $$boats.250a1=100$$ and  $$500a2=100or$$  $$a1=0.4ms$$−$$2$$ and $$a2=0.2ms$$−$$2The$$ relative acceleration: $$a=a1+a2=0.6ms$$−$$2Using$$ $$S=ut+12at2$$, we $$get120=(1/2)$$×$$0.6$$×$$t2$$  or  $$t=20s$$

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