First slide

Moment of intertia

Question

Rotational analogue of inertia in translatory motion is

Easy

A

mass
B

weight
C

moment of inertia
D

torque

Solution

For translatory motion
F = ma
Where F = Net external force
m = Mass (Inertia)
a = Linear acceleration
For rotational motion
$\tau$ = I α
where , $\tau$ = net external torque
I = moment of inertia
α = Angular acceleration
.: F → $\tau$ , a → α , m → I

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