First slide

Elastic Modulie

Question

A rubber ball is taken to a 100 m deep lake and its volume changes by 0.1 %. The bulk modulus of rubber is nearly:

Easy

A

1 X 10⁶ N/m²
B

1 x 10⁸ N/m²
C

1 x 10⁷ N/m²
D

1 x 10⁹ N/m²

Solution

$K = \frac{∆ P}{(- \frac{∆ V}{V})} = \frac{hρg}{(- \frac{∆ V}{V})} = \frac{100 \times 10^{3} \times 10}{10^{- 3}} = 10^{9} N / m^{2}$

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